Question

DETERMINE THE VERTEX AND THE X-INTERCEPT (or zeros) of
f(x) = (x-4)^2 - 9

Answer 1

Answer:

Vertex: (4,-9) .      zeros: 7,1

Step-by-step explanation:

a(x-h)^2+k .   vertex is (h,k) so it's (4,-9) in this case.

(x-4)^2-9=0 .  

(x-4)(x-4)-9=0

(x^2-8x+16)-9=0

x^2-8x+7=0

(x-7)(x-1)=0

x-7=0 . x-1=0

x=7 .  x=1