The height of the 6th bounce of the ball will be 1.2 feet.
A geometric sequence is a sequence in which each term is found by multiplying the preceding term by the same value.
The nth term of the geometric sequence is given by
[tex]T_{n} =ar^{n-1}[/tex]
Where,
[tex]T_{n}[/tex] is the nth term.
r is the common ratio
a is the first term
According to the given question.
During the first bounce, height of the ball from the ground, a = 6 feet
And, the each successive bounce is 72% of the previous bounce's height.
So,
During the second bounce, the height of ball from the ground
= 72% of 6
= [tex]\frac{72}{100} (6)[/tex]
= 0.72 × 6
= 4.32 feet
During the third bounce, the height of ball from the ground
= 72% of 4.32
= [tex]\frac{72}{100} (4.32)[/tex]
= 3.11 feet
Like this we will obtain a geometric sequence 6, 4.32, 3.11, 2.23,...
And the common ratio of the geometric sequence is 0.72
Therefore,
The sixth term of the geometric sequence is given by
[tex]T_{6} = 6(0.72)^{6-1}[/tex]
[tex]T_{6} =6(0.72)^{5}[/tex]
[tex]T_{6} = 6 (0.193)[/tex]
[tex]T_{6} = 1.16 feet[/tex]
[tex]T_{6} = 1.2[/tex] feet
Hence, the height of the 6th bounce of the ball will be 1.2 feet.
Find out more information about geometric sequence here:
https://brainly.com/question/11266123
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