Question

find two consecutive integers such that twice the first added to three times the second is equal to 83

Answer 1

first number- a second number- a + 2 a + a + 2 = 83 2a = 81 40.5 = 41 first number - 41 second number - 43

Answer 2

Let the first number=x and the second number =x+1 so
2(x)+3(x+1)=83                                         2(16)+3(17)=83
2x+3x+3=83                                                32+51=83
5x=83-3
5x=80
5x/5=80/5
x=16     16+1=17
Therefor the two consecutive integers are 16 and 17