Respuesta :
Hello!
[tex]\large\boxed{(4, -150)}[/tex]
We can solve for the vertex by completing the square. Begin by factoring out 6 from the equation to simplify the process:
6(x² - 8x) - 54 = 0
To complete the square, we must look at the first two terms (x² - 8x).
Remember that squaring a binomial uses the format a² + 2ab + b². We are already given a² and 2ab², so solve for b:
-8 / 2 = -4. This is the value of b.
We can rewrite this as:
(x - 4)²
However, this produces +16 which much be taken into account. Substitute (x - 4)² into the original equation:
6(x - 4)² - 54 = 0
Multiply 16 by the term in the front and subtract to cancel out this term:
6(x - 4)² - 54 - (6 · 16) = 0
Simplify:
6(x - 4)² - 150 = 0
In this form, the vertex is given as:
a(x - h)² + k, where h = x-coordinate and k = y-coordinate of the vertex.
In this instance, h = 4 and k = -150, so the coordinates of the vertex are:
(4, -150)
Answer:
y = 6x²-48x-54 has a vertex at (4,-150)
Step-by-step explanation:
There is no vertex. The solution set to 6x²-48x-54 = 0 is two points, (-1,0) and (9,0).
If you mean y = 6x²-48x-54, that is an up-opening parabola.
Put the equation into vertex form:
y = 6x²-48x-54
= 6(x²-8x)-54
= 6(x²-8x+4²)-6·4²-54
= 6(x-4)² - 150
vertex at (4,-150)