Molar mass :
CO₂ = 44.01 g/mol
LiHCO3 = 67.95 g/mol
Mole ratio: ( Calculate the mass of CO₂ ) :
2 LiHCO₃(s)→Li2CO₃(s)+H₂O(l)+CO₂(g)
2 x 67.95 g LiHCO₃ --------- 44.01 g CO₂
1.52 g LiHCO₃ ---------------- ??
Mass of CO₂ = 1.52 x 44.01 / 2 x 67.95
Mass of CO₂ = 66.8952 / 135.9
= 0.4922 g of CO₂
Number of moles:
mass CO₂ / molar mass CO₂
0.4922 / 44.01 => 0.01118 moles of CO₂
1 mole --------------------- 22.4 L ( at STP )
0.01118 moles ---------- ??
0.01118 x 22.4 / 1 => 0.250432 L
Therefore:
1 L --------------- 1000 mL
0.250432 --------- Volume
Volume = 0.250432 x 1000
= 250.432 mL
You are welcome! =)
