Question

Pulling on a spring with a force of 1.2 N causes a stretch of 6.4 cm. What is the spring constant for this spring?

Answer 1

Answer:

k=19 N/m

Explanation:

Use the equation F=kx for this problem and isolate k since that is what you're solving for (k=F/x). Plug in your values (F=1.2 N and x=0.064 m) and solve for k which is 19 N/m.

Answer 2

By using Hooke's law formula, the spring constant K for the spring is 18.75 N/m

The parameters given are :

Force F = 1.2N

Extension e = 6.4 cm

convert cm to m

e = 6.4 / 100

e = 0.064 m

Spring constant K = ?

From Hooke's law, It states that the extension is proportional to the force applied provided that elastic limit is not exceeded. That is,

F = Ke

Substitute all the parameters into the formula.

1.2 = 0.064K

Make K the subject of the formula

K = 1.2/0.064

K = 18.75 N/m

Therefore,  the spring constant K for this spring is 18.75 N/m

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