[tex] \text{We use formulas: }\\ \\
1) ~~ (a + b)(a^2 -ab + b^2) =a^3 + b^3 \\ \\
2)~~ \sin(2x) = 2\sin x \cos x \\ \\
3)~~ 1 =\sin^2(x) + cos^2(x) \\ \\
\text{We solve:} \\ \\
\Big(2-\sin(2x)\Big)\Big(\sin(x) + \cos(x)\Big) = 2\Big(\sin^3(x) + cos^3(x)\Big) \\ \\
\Big(2-2\sin(x)\cos(x)\Big)\Big(\sin(x) + \cos(x)\Big) = 2\Big(\sin^3(x) + cos^3(x)\Big) \\ \\
2\Big(1-\sin(x)\cos(x)\Big)\Big(\sin(x) + \cos(x)\Big) = 2\Big(\sin^3(x) + cos^3(x)\Big) [/tex]
[tex]2\Big(\sin^2(x)+\cos^2(x)-\sin(x)\cos(x)\Big)\Big(\sin(x) + \cos(x)\Big) = \\ 2\Big(\sin^3(x) + cos^3(x)\Big) \\ \\
2\Big(\sin^2(x)-\sin(x)\cos(x)+\cos^2(x)\Big)\Big(\sin(x) + \cos(x)\Big) = \\ 2\Big(\sin^3(x) + cos^3(x)\Big) \\ \\
\boxed{2\Big(\sin^3(x) + cos^3(x)\Big) = 2\Big(\sin^3(x) + cos^3(x)\Big) }[/tex]