what is the work for this question ?

Answer:
[tex]CA = 2.97516879[/tex]
[tex]AB = 6.786871837[/tex]
Step-by-step explanation:
[tex] \tan(B) = \frac{opposite}{adjacent} [/tex]
[tex] \tan(26) = \frac{CA}{6.1} [/tex]
[tex](6.1) \tan(26) = \frac{CA}{6.1} (6.1)[/tex]
[tex](6.1) \tan(26) = CA[/tex]
[tex]2.97516879 = CA[/tex]
[tex]CA = 2.97516879[/tex]
[tex]CA \approx3[/tex]
[tex] \cos(B) = \frac{adjacent}{hypotenuse} [/tex]
[tex] \cos(26) = \frac{6.1}{AB} [/tex]
[tex](AB) \cos(26) = \frac{6.1}{AB} (AB)[/tex]
[tex](AB) \cos(26) = 6.1[/tex]
[tex] \frac{(AB) \cos(26) }{ \cos(26) } = \frac{6.1}{ \cos(26) } [/tex]
[tex]AB = \frac{6.1}{ \cos(26) } [/tex]
[tex]AB = 6.786871837[/tex]
[tex]AB \approx6.8[/tex]