How would i do ✨this✨ ill mark brainliest

Step-by-step explanation:
Measure first the physical length of AB using a ruler then write it down like this:
LINE ¦ TRUE MEASURE ¦ RULER MEASURE
AB ¦ 4cm ¦ (write your ruler measurement)
BC ¦ 2.5cm ¦ (write here again)
CA ¦ x ¦ y
Solving for x:
CA² = 4² + 2.5² -2(4)(2.5)cos(75)
[tex]ca = \sqrt{16 + 6.25 - 20cos75} \\ = \sqrt{22.25 - 20cos75} \\ = 4.1320[/tex]
Solving for y:
[tex] \frac{ruler \: measure \: for \: 4cm}{4} = \frac{y}{4.1320} \\ 4y = 4.1320(ruler \: measure \: for \: 4cm) \\ y = 1.033 \times ruler \: measur \: for \: 4cm[/tex]
After you got all your measurements, use your protractor and measure 75° from left of B and with B as your center. Mark it and draw a line from B to the mark you just made for 75°.
From that line, draw the "ruler measure of 2.5cm." and the formed line would now be line BC.
Then, just connect the two endpoints (A and C)