elynSunnbre elynSunnbre
  • 30-10-2016
  • Mathematics
contestada

If f(5)=288.9 when r=0.05 for the function f(t)= pe^rt, then what is the approximate value of p?

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MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 09-11-2016

The general equation is: f(t)= [tex] pe^{rt} [/tex]

The given equation is: f(5)=288.9 when r = 0.05

Following the general equation, we know the following:

t=5, r = 0.05 and  [tex] pe^{rt} [/tex]  = 288.9

Substituting all unknowns, we can solve for p

[tex] pe^{0.05 * 5} [/tex]= 288.9

Solving for p,

p = 225

Answer Link
acelynnshamrockk
acelynnshamrockk acelynnshamrockk
  • 14-10-2019

Answer:225

Step-by-step explanation:

Apex

Answer Link

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