Answer:
f⁻¹(x) = 2ˣ / 9
Step-by-step explanation:
f(x) = log₂ (9x)
y = log₂ (9x)
swap y and x: x = log₂ (9y)
solve y: 9y = 2ˣ y = 2ˣ / 9
f⁻¹(x) = 2ˣ / 9
The equation of the inverse of the function f(x) = log2 (9x) should be considered as the [tex]f^{-1}(x) = 2^x / 9[/tex]
Since
f(x) = log₂ (9x)
So,
y = log₂ (9x)
Now
swap y and x so x = log₂ (9y)
And, now we have to solve for y
9y = 2ˣ
y = 2ˣ / 9
f⁻¹(x) = 2ˣ / 9
Hence, The equation of the inverse of the function f(x) = log2 (9x) should be considered as the [tex]f^{-1}(x) = 2^x / 9[/tex]
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