Answer:
<QRP = 48.2°
Step-by-step explanation:
Given:
PR = 18 cm
QR = 12 cm
Required:
<QRP = angle R
Solution:
Reference angle = <R (<QRP)
Adjacent side length = 12 cm
Hypotenuse = 18 cm
Thus:
Cos (R) = 12/18
cos (R) = 0.6667
[tex] R = Cos^{-1}(0.6667) [/tex]
[tex] R = 48.1871227 [/tex]
<QRP = 48.2° (nearest tenth)
