mccottertateciara mccottertateciara
  • 28-01-2021
  • Mathematics
contestada

Solve the system for a and b:
9 = ab^2
-72=ab^5

Respuesta :

jimrgrant1 jimrgrant1
  • 28-01-2021

Answer:

a = [tex]\frac{9}{4}[/tex] , b = - 2

Step-by-step explanation:

Given the 2 equations

9 = ab² → (1)

- 72 = a[tex]b^{5}[/tex] → (2)

Divide (2) by (1)

[tex]\frac{-72}{9}[/tex] = [tex]\frac{ab^5}{ab^2}[/tex]

- 8 = b³ ( take the cube root of both sides )

[tex]\sqrt[3]{-8}[/tex] = b , that is

b = - 2

Substitute b = - 2 into (1) and solve for a

9 = a(- 2)² = 4a ( divide both sides by 4 )

[tex]\frac{9}{4}[/tex] = a

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