Question

$(\frac{1}{4} m^{2} n)^{3} * (-32m^{2}n)$

PLEASE PROVIDE AN EXPLANATION, I'M UNSURE OF HOW TO FIND THE ANSWER

Answer 1

Answer:

               $\bold{(\frac14m^2n)^3*(-32m^2n)=-\frac12m^8n^4}$

Step-by-step explanation:

                                $(\frac14m^2n)^3*(-32m^2n)=\\\\=(\frac14)^3*(m^2)^3*n^3*(-32)*m^2*n=\\\\= \frac1{64}*m^{2\cdot3}*n^3*(-32)*m^2*n=\\\\= \frac1{64}*(-32)*m^{6}*m^2*n^3*n=\\\\=-\frac{32}{64}*m^{6+2}*n^{3+1}=\\\\=-\frac12m^8n^4$