write an equation in slope intercept form that represents the line shown

Answer:
[tex]y - 2 = -\frac{1}{3}(x + 3)[/tex]
Step-by-step explanation:
The equation of a line, in slope-intercept is given by:
[tex]y - y_0 = m(x - x_0)[/tex]
In which [tex](x_0,y_0)[/tex] is a point in the line and m is the slope.
We have these following points:
(-3,2), (0,1)
I am going to use [tex](x_0,y_0) = (-3,2)[/tex]
So
[tex]y - 2 = m(x - (-3))[/tex]
[tex]y - 2 = m(x + 3)[/tex]
Finding the slope
The slope, given two points, is given by the change in y divided by the change in x. In this question:
Points (-3,2) and (0,1).
Change in y: 1 - 2 = -1
Change in x: 0 - (-3) = 0 + 3 = 3
So
[tex]m = \frac{-1}{3} = -\frac{1}{3}[/tex]
So the equation of the line is:
[tex]y - 2 = -\frac{1}{3}(x + 3)[/tex]