Kevin works as a part-time vendor selling wallets for $20 each and hats for $15 each. He needs to earn a minimum of $450 per week to cover his expenses.

The inequality that represents this situation is graphed here, where x is the number of wallets sold and y is the number of hats sold.

20x + 15y ≥ 450



Determine which points are valid solutions and which are invalid, and then drag them to the correct location on the table.

Kevin works as a parttime vendor selling wallets for 20 each and hats for 15 each He needs to earn a minimum of 450 per week to cover his expenses The inequalit class=
Kevin works as a parttime vendor selling wallets for 20 each and hats for 15 each He needs to earn a minimum of 450 per week to cover his expenses The inequalit class=

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Answer:

Valid is (32,12) , (6,36) , (20,20)

Invalid is (-4,40) , (36,-8), (15,22.5)

Step-by-step explanation:

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Answer:

Valid solutions

(20,20)

(32,12)

(6,36)

Invalid solutions

(-4,40)

(36,-8)

(15,22.5)

Step-by-step explanation:

First, plot each point on the graph to determine whether it lies in the solution set.

All the points lie within the shaded region, so they are all solutions to the inequality.

Now, consider restrictions to the domain and range. Since x is the number of wallets and y is the number of hats, each x- and y-value must be a positive whole number. That leaves only the following points as valid solutions.

(20,20)

(32,12)

(6,36)

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