[tex]4.9 \times 10^{23}[/tex] are present in 18.4L of argon (Ar).
To calculate the amount of particles present in a given amount of volume, it is necessary to have knowledge of the molar volume:
[tex]1 mol = 22.4L[/tex]
Thus, in 22.4L there is 1 mol of an element, remembering that:
[tex]1 mol = 6\times10^{23}[/tex] particles
In this way, it is enough to relate the value of the molar volume given with the value requested by the question:
[tex]\frac{6\times10^{23}particles}{xparticles} = \frac{22.4L}{18.4L}[/tex]
[tex]x = 4.9 \times 10^{23}[/tex] particles
So, [tex]4.9 \times 10^{23}[/tex] are present in 18.4L of argon (Ar).
Learn more about mole calculation in: brainly.com/question/15209553
