Question

. What is the percent by mass of iron in the compound Fe2O32 The molar mass Fe2O3 is 159,69 g/mol. of​

Answer 1

Answer:

Percent by mass is 69.42% Fe

Explanation:

If the molar mass is 159.69 grams per mol, and our goal is to find the percent by mass of iron, then we need to find the mass of iron first. We will calculate the amu of Iron and divide that by the total molar mass of Fe2O3.. and then multiply by 100 and write with a % in order to find the percent by mass (percent composition)

Fe2 = 2(55.845) = 111.69

111.69/159.69 = 0.69941762164

0.69941762164 * 100 = 69.42% Fe

Answer 2

The study of chemicals is called chemistry.

The correct answer to the question is Percent by mass is 69.42% Fe

What is a molecule?

• A molecule is an electrically neutral group of two or more atoms held together by chemical bonds. Molecules are distinguished from ions by their lack of electrical charge.

If the molar mass is 159.69 grams per mole, and our goal is to find the percent by mass of iron, then we need to find the mass of iron first.

We will calculate the AMU of Iron and divide that by the total molar mass of Fe2O3. and then multiply by 100 and write with a % in order to find the percent by mass (percent composition)

$Fe2 = 2(55.845) = 111.69\\\\\\frac{111.69}{159.69} = 0.69941762164\\\\0.69941762164 * 100 = 69.42% Fe$

Hence, the correct option answer is 69.42.

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https://brainly.com/question/5763151