Find the values of x and y. Pls helpI’m helpless at math

Answer:
Step-by-step explanation:
From the given right-angle triangle
The angle = ∠60°
The hypotenuse = x
Determining the value of x:
Using the trigonometric ratio
cos 60° = adjacent / hypotenuse
substituting adjacent = 1/2 and hypotenuse = x
[tex]cos\:60^{\circ }=\:\:\frac{\frac{1}{2}}{x}[/tex]
[tex]\cos \left(60^{\circ \:}\right)=\frac{1}{2x}[/tex]
[tex]\frac{1}{2}=\frac{1}{2x}[/tex] ∵ cos (60°) = 1/2
[tex]2x=2[/tex]
Dividing both sides by 2
[tex]\frac{2x}{2}=\frac{2}{2}[/tex]
Simplify
[tex]x=1[/tex]
Thus, the value of hypotenuse x is:
x = 1
Determining the value of y:
Using the trigonometric ratio
sin 60° = opposite / hypotenuse
As we have already determined the value of hypotenuse x = 1
substituting opposite = y and hypotenuse = 1
sin 60° = y/1
y = 1 × sin 60°
[tex]y=\frac{\sqrt{3}}{2}[/tex] ∵ [tex]\sin \left(60^{\circ \:}\right)=\frac{\sqrt{3}}{2}[/tex]
Therefore, the value of y is:
[tex]y=\frac{\sqrt{3}}{2}[/tex]
Summary: