Answer:
177.3kg C₂₁H₄₄
Explanation:
Based on the chemical reaction:
C₂₁H₄₄ → 3C₂H₄ + C₁₅H₃₂
Where 1 mole of C₂₁H₄₄ produce 3 moles of ethene, C₂H₄.
To solve this question we need to determine the moles of ethene in 50.4kg. 1/3 these moles are the moles of C₂₁H₄₄ that must be added:
Moles Ethene -Molar mass: 28.05g/mol-
50.4kg = 50400g * (1mol / 28.05g) = 1796.8 moles of ethene
Moles C₂₁H₄₄:
1796.8 moles of ethene * (1 mol C₂₁H₄₄ / 3 mol C₂H₄) = 589.93 moles C₂₁H₄₄
Mass C₂₁H₄₄:
589.93 moles C₂₁H₄₄ * (296g / mol) = 177283g =
177.3kg C₂₁H₄₄
