Respuesta :
The required number of cows x = 30 and chickens is y = 16 .
Given that,
A farm raises cows and chickens.
The farmer has a total of 46 animals.
One day he counts the legs of all his animals and realizes he has a total of 156 legs.
We have to find,
How many cows does the farmer have.
According to the question,
Let, The number of cows = x
And the number of chickens =y.
Then,
The number of cows + The number of chickens = The farmer has a total of 46 animals.
x + y = 46
The cows has 4 legs, and the chickens has 2 legs.
He has a total of 156 legs.
Then,
The number of Cow's legs + The number of chickens legs = The total number of legs farmer have.
4x + 2y = 156
On solving both the equation,
x + y = 46
y = 46 - x
Substitute the value of y in the equation 2.
[tex]4x + 2y = 156\\\\4x + 2(46 - x) = 156\\\\4x + 96 - 2x = 156\\\\2x = 156 - 96\\\\2x = 60\\\\x = \dfrac{60}{2}\\\\x = 30[/tex]
The farmer have 30 cows.
And substitute the value of x in the equation 1,
[tex]x + y = 46\\\\30 + y = 46\\\\y = 46-30\\\\y = 16[/tex]
The farmer have 16 chickens.
Hence, The required number of cows x = 30 and chickens is y = 16 .
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