Question

how do you solve polynomial equation by factoring
2x^3 - 12x^2 = 32x - 192

Answer 1

$2x^3 - 12x^2 = 32x - 192\\ 2x^3-12x^2-32x+192=0\\ 2(x^3-6x^2-16x+96)=0\\ 2(x^2(x-6)-16(x-6))=0\\ 2(x^2-16)(x-6)=0\\ 2(x-4)(x+4)(x-6)=0\\ x=4 \vee x=-4 \vee x=6$