A bag contains 4 sour-apple candies and 3 watermelon candies. One piece of candy is chosen at random and returned to the bag. Then a second piece of candy is chosen at random What is the probability that both pieces of candy chosen will be sour -apple ?

Respuesta :

Answer: [tex]\dfrac{16}{49}[/tex]

Step-by-step explanation:

Given: A bag contains 4 sour-apple candies and 3 watermelon candies.

Total candies = 4+3 = 7

If replacement of candy is done, then the probability of getting sour apple will be the same and independent each time .

Probability of selecting sour apple candy= [tex]\dfrac{\text{Number of sour apple candy}}{\text{Total}}[/tex]

[tex]=\dfrac47[/tex]

Now , the probability that both pieces of candy chosen will be sour -apple  =[tex]\dfrac47\times\dfrac{4}{7}=\dfrac{16}{49}[/tex]

hence, required probability = [tex]\dfrac{16}{49}[/tex]

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