Question

Find the volume of a gas at 800.0 mm Hg and 40.0 °C if its volume at 720.0 mm Hg and 15 °C is 6.84 L.

Answer 1

Answer:

2 C6H6  + 15 O2  (  12 CO2  + 6 H2O

Explanation:

Answer 2

6.156 L is the volume of a gas at 800.0 mm Hg and 40.0 °C if its volume at 720.0 mm Hg and 15 °C is 6.84 L.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

$P_1V_1=P_2V_2$

$P_1$ = 800.0 mm Hg

$V_1$ = ?

$P_2$ = 720.0 mm Hg

$V_2$ = 6.84 L

Putting all the value in the equation;

$P_1V_1=P_2V_2$

800.0 mm Hg X $V_1$ = 720.0 mm Hg X 6.84 L

$V_1$ =6.156 L

6.156 L is the volume of a gas at 800.0 mm Hg and 40.0 °C if its volume at 720.0 mm Hg and 15 °C is 6.84 L.

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