Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atmosphere respectively.
1 mole of every gas occupy volume at STP = 22.4 L
The balanced chemical reaction is:
[tex]2C_6H_6(I)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)[/tex]
3909.9 kJ of of energy is produced by = [tex]15\times 22.4=336L[/tex]
100 kJ of oxygen gas are needed to produce = [tex]\frac{336}{3909.9}\times 100=8.59L[/tex]
