Question

1 BRAINLIEST and 10 points!
Mr. Richard owns an orchard that has a rectangular fence. The orchard is 35 feet long

and 18 feet wide. If he walks across the diagonal length of the orchard, how much

distance would he cover?

Answer 1

Answer:

≈40.25 Feet

Step-by-step explanation:

The diagnal length of the orchard is the hypotenuse of the triangal with side lengths of 36 and 18.

Therefore, to calculate that, set the hypotenuse as x.

36²+18²=x²

√1620≈ 40.25yards

If I'm wrong I'm so sorry!  I'm wrong sorry

If I'm right Thank you

(lost)

Answer 2

Answer:

39.357 feet to 3dp

Step-by-step explanation:

for this question you would use pythagoras's theorm

$\sqrt{18^{2} +35^{2} }$

hope this helps :)