Using MS Excel, the function is graphed from t=0 seconds to t=10 seconds. The figure is shown below.
For the second question, the equation given is
[tex]y = 1.79 e^{-0.22tcos(4.9t)} [/tex]
When y is 3 inches or 0.25 foot, t is
[tex]0.25 = 1.79 e^{-0.22tcos(4.9t)} [/tex]
Simplify by taking ln for both sides:
[tex]ln(e^{-0.22tcos(4.9t)})=ln \frac{y}{1.79} [/tex]
Solving for t,
t = 1.34 seconds