Question

A rectangle has a length that is 4 meters more than the width. The area of the rectangle is 117 square meters. Find the dimensions of the rectangle.

Answer choices are on picture.

Answer 1

Answer:

Its the first choice. Width:9 Length:13

Step-by-step explanation:

If the length is 4 meter more than the width than that means whatever the width is you must add 4 to it, in this case the width is 9 so add 4 to it which equals 13. If the length matches your answer it is the correct choice.

Answer 2

The area of a rectangle is the product of its dimensions. The dimension of the rectangle is: $Length = 13m$ and $Width = 9m$

Given that:

$L =4 + W$

$Area = 117$

The area of a rectangle is:

$Area = L \times W$

So, we have:

$L \times W= 117$

Substitute $L =4 + W$

$(4 + W) \times W = 117$

Expand

$4W + W^2 = 117$

Rewrite as:

$W^2 + 4W- 117 = 0$

Expand

$W^2 + 13W - 9W - 117 = 0$

Factorize

$W(W + 13) - 9(W + 13) = 0$

Factor out W + 13

$(W - 9)(W + 13) = 0$

Solve for W

$W = 9$ or $W = -13$

The dimension cannot be negative.

So:

$W = 9$

Recall that:

$L =4 + W$

$L = 4 + 9$

$L = 13$

So, the dimension of the rectangle is:

$Length = 13m$

$Width = 9m$

Read more about areas at:

https://brainly.com/question/15218510