Answer:
Follows are the solution to the given question:
Explanation:
The rectangular part has a length of [tex]14 \ mm[/tex] and its rectangular part has a width of [tex]4.98 \ mm[/tex].
In option A
Calculating the area of the rectangular throgh the given piece:
[tex]\to A_R = WL=(14 mm) (4.98 mm) =69.72 \ mm^2[/tex]
In option B
Calculating the ratio of rectangle's width which is rectangle's length:
[tex]\to R_{WL}=\frac{W}{L}= \frac{4.98 \ mm}{14 \ mm} = 0.3557[/tex]
So, the ratio of rectangle's width to rectangle's length is 0.3557 .
In option C
Calculating the Perimeter of the rectangle:
[tex]\to P_R=2(W+L)=2(14 \ mm+ 4.98 \ mm)= 2(18.98) = 37.96 \ mm[/tex]
In option D
Calculating the difference between length and width:
[tex]\to D_{LW} = L- W = 14\ mm -4.98 \ mm =9.02 \ mm[/tex]
In option E
Calculating the ratio of length to width:
[tex]\to R_{LW}=\frac{L}{W} =\frac{14\ mm}{4.98 \ mm} = 2.811[/tex]