Question

The concession stand at a football game sells hot dogs and drinks. It costs $4.25 for 2 hot dogs and 1 drink. It costs $7.00 for 3 hot dogs and 2 drinks. Which of the following systems of equations can be solved to determine the cost, h, of each hot dog and the cost, d, of each drink

Answer 1

Answer:

h = $1.50

d = $1.25

Step-by-step explanation:

$1.50 + $1.50 = $3 + $1.25 = $4.25

$1.50 + $1.50 + $1.50 = $4.50 + $1.25 + $1.25 = $7

Answer 2

Answer:

2h + 1d = 4.25

3h + 2d = 7.00

Step-by-step explanation:

-3(2h + 1d) = -3(4.25)

2 (3h + 2d) = 2(7.00)

-6h - 3d = -12.25

6h + 4d = 14

if we add them together we get D = 1.75

Checking:

2h + 1(1.75) = 4.25

2h + 1.75 = 4.25

2h = 2.5

h = 1.25

1.25 times 2 plus 1.75 = 4.25