The diagonal length of a rectangle is 25 inches, and the length of the rectangle is 9 inches.

Which measurement is closest to the width of this rectangle in inches?

A) 15.8
B) 16
C) 23.3
D) 34

Respuesta :

Answer:

Option C is the right answer.

Step-by-step explanation:

Given that:

Length of diagonal = 25 inches

Length of rectangle = 9 inches

Width of rectangle will be one of the two legs of right angled triangle and the diagonal will be the hypotenuse.

Using Pythagorean theorem;

[tex]a^2+b^2=c^2\\(9)^2+w^2=(25)^2\\81 + w^2 = 625 \\w^2 = 625-81\\w^2 = 544[/tex]

Taking square root;

[tex]\sqrt{w^2}=\sqrt{544}\\w=23.3[/tex]

Therefore,

Option C is the right answer.

We will see that the width of the rectangle is 23.3, so the correct option is C.

How to get the width if we know the length and the diagonal?

For a rectangle of length L and width W the diagonal length is given by:

D = √( W^2 + L^2)

Rewriting this for the width we get:

W = √(D^2 - L^2)

Here we know that:

D  = 25 in

L = 9 in

Replacing that in the equation above we get:

W = √( (25 in)^2 - (9 in)^2 ) = 23.3

So the correct option is C.

If you want to learn more about rectangles you can read:

https://brainly.com/question/17297081

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