Question

The area of a rectangle is 35x4y10 square feet. If the length of the rectangle is 7x2y5 feet, which expression represents the width of the rectangle?

Answer 1

Answer: $5x^2y^5$

Step-by-step explanation:

Given: Area of rectangle = $35x^4y^{10}$ square feet

Length of rectangle= $7x^2y^5$

We know that,

Width of rectangle = $\dfrac{\text{Area of rectangle}}{\text{Length}}$

Then,

Expression of width= $\dfrac{35x^4y^{10}}{7x^2y^5}$

$=\dfrac{5x^{4-2}y^{10-5}}{1}\ \ \ \ [\frac{x^m}{x^n}=x^{m=n}]\\\\=5x^2y^5$

Hence, the expression for width of the rectangle = $5x^2y^5$