Question

How many atoms are there in 15.0 grams of Sulfur (S)?


A) 7.99×10−22 atoms of S

B) 7.77×10−25 atoms of S

C) 2.82×1023 atoms of S

D) 9.03×1024 atoms of S

Answer 1

Answer:

C

Explanation:

Mol x Avogadro's number

Mol : mass / molar mass

Avogadro's no: 6.02E+23

Answer 2

In 15.0 g of sulfur, there are 2.82 × 10²³ atoms of S (C).

We want to calculate the number of atoms in 15.0 g of sulfur. We will need 2 conversion factors.

What is a conversion factor?

A conversion factor is an arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.

To convert 15.0 g of sulfur into atoms, we need to consider the following conversion factors:

• The molar mass of S is 32.07 g/mol.
• 1 mol contains 6.02 × 10²³ atoms (Avogadro's number).

$15.0g \times \frac{1mol}{32.07g} \times \frac{6.02 \times 10^{23}atoms }{1mol} = 2.82 \times 10^{23}$

In 15.0 g of sulfur, there are 2.82 × 10²³ atoms of S (C).

Learn more about Avogadro's number here: https://brainly.com/question/15989275