Reasons
4
4
K
Glven: N is the midpoint of JL;
N is the midpoint of KM;
JL = KM
N
Prove: KN = NL
M
Statements
Reasons
1.
N is the midpoint of JL;
N is the midpoint of KM;
JL = KM
1. Given
2.
JN = NL;
KN = NM
2.
3.
3. Segment Addition Postulate
4. KN + NM = JL
4.
5.
5. Transitive Property
6. KN + KN = NL + NL
6.
7.
7. Simplify
8. KN = NL
8.
Gina Wilson (All Things Algebra). 20

Reasons 4 4 K Glven N is the midpoint of JL N is the midpoint of KM JL KM N Prove KN NL M Statements Reasons 1 N is the midpoint of JL N is the midpoint of KM J class=

Respuesta :

Answer:

(1) The two column proof is presented here as follows;

Statement         [tex]{}[/tex]                                Reasons

1. C is the midpoint of [tex]\overline {AE}[/tex]         [tex]{}[/tex]           Given  

  B is the midpoint of [tex]\overline {AC}[/tex]         [tex]{}[/tex]          

  D is the midpoint of [tex]\overline {CE}[/tex]         [tex]{}[/tex]          

2. AC = CE, AB = BC, CD = DE        [tex]{}[/tex]      Definition of midpoint

3. AB + BC = AC, CD + DE = CE      [tex]{}[/tex]       Segment addition postulate

4. CD + DE = AC        [tex]{}[/tex]                             Substitution property of equality

5. AB + BC = CD + DE  [tex]{}[/tex]                          Substitution property of equality

6. BC + BC = CD + CD          [tex]{}[/tex]                  Substitution property of equality

7. 2·BC = 2·CD         [tex]{}[/tex]                               Addition of two identical quantities

8. BC = CD  [tex]{}[/tex]                                            Division property of equality

9. BC ≅  CD     [tex]{}[/tex]                                       Definition of Congruence

(2) The two column proof for the triangular geometric figure is presented here as follows;

Statement         [tex]{}[/tex]                                        Reasons

1. 2·WV = XY; 2·YZ = XW; WV = YZ   [tex]{}[/tex]      Given

2.  2·WV = 2·YZ        [tex]{}[/tex]                                Multiplication property

3. XY = XW        [tex]{}[/tex]                                       Substitution Property

4. XW + WV = XV       [tex]{}[/tex]                              Segment Addition Property

XY + YZ = XZ

5. XW + WV = XV      [tex]{}[/tex]                              Substitution Property

XW + WV = XZ

6. XV = XZ       [tex]{}[/tex]                                        Substitution Property

Explanation:

ACCESS MORE
EDU ACCESS
Universidad de Mexico