Respuesta :

Answer: The area of the parallelogram ABCD = 32.4 sq. cm

Step-by-step explanation:

Given: In parallelogram ABCD, AB = 7.2 cm and the perpendicular drawn from C (altitude) on AB is 4.5 cm i.e.e height =4.5 cm.

Area of parallelogram = [tex](Base \times height)[/tex]

Then, Area of parallelogram ABCD = [tex]7.2\times4.5[/tex]

= [tex]32.4\ cm^2[/tex]

Therefore , the area of the parallelogram ABCD = 32.4 sq. cm

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