Answer: The area of the parallelogram ABCD = 32.4 sq. cm
Step-by-step explanation:
Given: In parallelogram ABCD, AB = 7.2 cm and the perpendicular drawn from C (altitude) on AB is 4.5 cm i.e.e height =4.5 cm.
Area of parallelogram = [tex](Base \times height)[/tex]
Then, Area of parallelogram ABCD = [tex]7.2\times4.5[/tex]
= [tex]32.4\ cm^2[/tex]
Therefore , the area of the parallelogram ABCD = 32.4 sq. cm