Answer:
1)The equation of the Parallel line is 2x -y -4=0
2) The equation of the perpendicular line of the given line x+2y+8=0
Step-by-step explanation:
Step(i):-
Given function f(x) = 2x+3 and passes through (0,-4)
Let y =f(x) = 2x+3
y = 2x+3
⇒ 2x -y +3=0
The equation of the parallel line of the given line 2x - y +k =0
This line is passes through the point (0,-4)
⇒ 2 (0) -(-4)+k=0
4 +k=0
⇒ k =-4
The equation of the Parallel line is 2x -y -4=0
2)
Step(ii):-
Given function f(x) = 2x+3
Let y = 2 x + 3
2x - y +3=0
The equation of the perpendicular line bx -ay +k=0
The equation of the perpendicular line of the given line -x-2y +k =0
This line is passes through the point (0,-4)
⇒ (0) -2(-4)+k=0
8 +k=0
⇒ k =-8
The equation of the perpendicular line of the given line -x-2y -8 =0
The equation of the perpendicular line of the given line x+2y+8=0
