Answer:
Each of these equations solves as 1, because each one of them is an instance of the same expression being divided by itself.
This will always give you a value of 1, as long as the denominator does not end up with a zero value.
Take for instance the third question:
[tex]\frac{p^4}{p^4}\\= p^4 \times p^{-4}\\= p^{(4 - 4)}\\= p^0\\= 1[/tex]
This stands true with all three questions.
HOWEVER
I say this assuming that the 5 following the first brackets in the first question is meant to be an exponent, and not a multiple. Given that the norm is to make any numeric multiples precede the brackets, I assume it is an exponent. and we're good.
It's not using superscript though, which could mean that they want it multiplied by five instead of raised to the power of.
If that's case, we can solve it the same way we solved question 20. If the bases are the same, then when multiplying or dividing the terms, you can simply add or subtract the exponents respectively:
[tex]\frac{(4x + 2y)\times5}{(4x + 2y)^5}\\= 5(4x + 2y) \times (4x + 2y)^{-5}\\= 5(4x + 2y)^1 \times (4x + 2y)^{-5}\\= 5(4x + 2y)^{1 - 5}\\= 5(4x + 2y)^{-4}\\= \frac{5}{(4x + 2y)^{4}}[/tex]
Again, this is probably not the correct answer for question 18, as that 5 is almost guaranteed to be meant as an exponent. If it is instead a coefficient though, then this would be the answer to it.
