Answer:
[tex](81x^4y^{16})^{\frac{1}{2}} = 9 x^2 y^8[/tex]
Step-by-step explanation:
Given
[tex](81x^4y^{16})^{\frac{1}{2}}[/tex]
Required
Determine an equivalent expression
Express 81 as [tex]9^2[/tex]
[tex](9^2x^4y^{16})^{\frac{1}{2}}[/tex]
Apply law of indices
[tex]9^2^{\frac{1}{2}} * x^4^{\frac{1}{2}} * y^{16}^{\frac{1}{2}}[/tex]
[tex]9^{\frac{2*1}{2}} * x^{\frac{4*1}{2}} * y^{\frac{16*1}{2}}[/tex]
[tex]9^{\frac{2}{2}} * x^{\frac{4}{2}} * y^{\frac{16}{2}}[/tex]
[tex]9^1 * x^2 * y^8[/tex]
[tex]9 * x^2 * y^8[/tex]
[tex]9 x^2 y^8[/tex]
Hence:
[tex](81x^4y^{16})^{\frac{1}{2}} = 9 x^2 y^8[/tex]