Answer: 5i√3
i is the square root of -1. Factor that out, along with 5, the square root of 25. That leaves 3 inside the radical.
Step-by-step explanation:
Separate the factors of the number inside the radical, look for perfect squares:
[tex]\sqrt{-1*25*3}[/tex]
If the number is negative, factor -1, and use i as the imaginary square root of negative 1. and move that out to the left of the radical.
[tex]i\sqrt{(25)(3)}[/tex]
If there is a perfect square, take the square root and move that out to the left of the i outside the radical.
Leave any other values inside the radical.
[tex]5i\sqrt{3}[/tex]
