Question

Which graph shows rotational symmetry?
On a coordinate plane, a sine curve goes through one cycle and is represented by f (x). The curve has a minimum of (2, negative 2), a maximum of (negative 2, 2), and goes through (0, 0).
On a coordinate plane, the function g(x) has two connected curves. The first curve goes through point (negative 3, negative 2) to (0, 0). The second curve goes from (0, 0) through (2, 3).
On a coordinate plane, the function h (x) is a v shape that opens down. The function has a vertex at (0,0) and goes through (negative 4, negative 4) and (4, negative 4).
On a coordinate plane, a parabola opens up. It goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4).

Answer 1

The graph that have a rotational symmetry is (d) on a coordinate plane, a parabola opens up. It goes through (-2, 4), has a vertex at (0, 0), and goes through (2, 4).

What is a rotational symmetry?

A rotational symmetry is a term used to describe a graph that remains the same when rotated

For a graph to have a rotational symmetry, then the graph must be a parabola or an absolute value graph.

And the graph must have its vertex at the origin

Hence, the graph that have a rotational symmetry is (d) on a coordinate plane, a parabola opens up. It goes through (-2, 4), has a vertex at (0, 0), and goes through (2, 4).

Read more about rotational symmetry at:

https://brainly.com/question/15178808

Answer 2

Answer:

B on edge

Step-by-step explanation: