Question

What is the solution to the following bernoulli de?
\[t^2 dy/dx+y^2=ty\]
It looks like it is homogenous because if you divide through by \[t^2\] it will be \[y/t\] all over. Also if it's a bernoulli, wouldn't \[v=y\], which isn't very useful. Any thoughts?

Answer 1

Here t is constant only x and y are variables so it reduces to

dy/ty-y^2 = 1/t^2(dx)

just solve it taking t as constant.

hope this helps