Question

double integral of e^y/x dy dx with outer limits as 0 and 2 and inner limits as 0 and x^2 ???

Answer 1

$\int\limits^2_0 \int\limits^{x^2}_0 {\frac{e^y}{x}} \, dydx = \int\limits^2_0 (\frac{e^{x^2}-1}{x})} \, dx = 8.83$