Question

Express answer in exact form.

Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius.

Answer 1

Area of circle = πr²
= 64π
The cord will subtend a semicircle of diameter 8", radius 4". The area of this semicircle:
1/2 πr²
= 0.5 x 4² x π
= 8π
Area of larger region = area of circle - area of semicircle
= 64π - 8π
= 56π inch²

Answer 2

Answer:

$A=(\frac{160}{3}\pi+ 80\sqrt{3}) inches^2$

Step-by-step explanation:

I answered this question which says the area of the smaller part:

https://brainly.com/question/4114143

Pretty much take that answer and multiply it by 5.

The reason you multiply it by 5 is because a circle can fit 6 equilateral triangles. The smaller section is one of those equilateral triangles so 5 minus 1 is 6. I hope all of this makes sense.