Respuesta :
Molecular:
2HNO3 + Ba(OH)2 --> Ba(NO3)2 + 2H2O
Ionic: you need to know the solubility phases of all compounds for this step
2HNO3(aq) + Ba(OH)2(s) --> Ba(NO3)2(aq)+ 2H2O(l)
Only separate aqueous (aq)
2H+ + 2NO3- + Ba(OH)2(s) --> Ba 2+ + 2NO3- + 2H2O(l)
Net ionic: eliminate all compounds that are the same on both sides (2NO3-)
You are left with
2H+ + Ba(OH)2(s) --> Ba2+ + 2H2O(l)
2HNO3 + Ba(OH)2 --> Ba(NO3)2 + 2H2O
Ionic: you need to know the solubility phases of all compounds for this step
2HNO3(aq) + Ba(OH)2(s) --> Ba(NO3)2(aq)+ 2H2O(l)
Only separate aqueous (aq)
2H+ + 2NO3- + Ba(OH)2(s) --> Ba 2+ + 2NO3- + 2H2O(l)
Net ionic: eliminate all compounds that are the same on both sides (2NO3-)
You are left with
2H+ + Ba(OH)2(s) --> Ba2+ + 2H2O(l)
For the given reaction ; HNO₃ + Ba(OH)₂
- Molecular reaction = 2HNO₃ + Ba(OH)₂ ---> Ba(NO₃)₂ + 2H₂O
- Ionic reaction = 2H⁺ + 2NO₃⁻ + Ba(OH)₂(s) ---> Ba²⁺ + 2NO₃⁻ + 2H₂O(l)
- Net ionic reaction = 2H⁺ + Ba(OH)₂(s) --> Ba²⁺ + 2H₂O(l)
The molecular reaction of the the given reaction can be expressed as
Molecular reaction = 2HNO₃ + Ba(OH)₂ ---> Ba(NO₃)₂ + 2H₂O while
The Ionic equation of the reaction is written as
step 1 : determine the solubility phases of the compounds involved in the given reaction
2HNO₃(aq) + Ba(OH)₂(s) --> Ba(NO₃)₂(aq)+ 2H₂O(l)
step 2 when writing ionic equations we separate the aqueous solution int its respective ions
∴ The ionic equation becomes ;
2H⁺ + 2NO₃⁻ + Ba(OH)₂(s) ---> Ba²⁺ + 2NO₃⁻ + 2H₂O(l)
The net Ionic reaction equation is written as
Step 1 ; remove compounds found on both sides of the reaction equation.
∴ The net ionic equation becomes
2H⁺ + Ba(OH)₂(s) --> Ba²⁺ + 2H₂O(l)
Hence we can conclude that the
Molecular reaction = 2HNO₃ + Ba(OH)₂ ---> Ba(NO₃)₂ + 2H₂O
Ionic reaction = 2H⁺ + 2NO₃⁻ + Ba(OH)₂(s) ---> Ba²⁺ + 2NO₃⁻ + 2H₂O(l)
Net ionic reaction = 2H⁺ + Ba(OH)₂(s) --> Ba²⁺ + 2H₂O(l)
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