Respuesta :
f(x)= 3(x-4)^2 -38
Once you take out the GCF of 3 from the first two terms, then do completing the square.

Answer: The required vertex form of the given function is
[tex]f(x)=3(x-4)^2-38,[/tex] where the vertex is (4, -38).
Step-by-step explanation: Given that the first steps in writing [tex]f(x)=3x^2-24x+10[/tex] in vertex form are shown.
[tex]f(x)=3(x^2-8x)+10~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We are to write the given function in vertex form.
We know that
the vertex form of a function g(x) with vertex at the point (h, k) is given by
[tex]g(x)=a(x-h)^2+k.[/tex]
Therefore, from equation (i), we get
[tex]f(x)=3(x^2-8x)+10\\\\\Rightarrow f(x)=3(x^2-8x+16)-3\times 16+10\\\\\Rightarrow f(x)=3(x-4)^2-48+10\\\\\Rightarrow f(x)=3(x-4)^2-38.[/tex]
Thus, the required vertex form of the given function is
[tex]f(x)=3(x-4)^2-38,[/tex] where the vertex is (4, -38).