Respuesta :

bcalle
f(x)= 3(x-4)^2 -38 Once you take out the GCF of 3 from the first two terms, then do completing the square.
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Answer:  The required vertex form of the given function is

[tex]f(x)=3(x-4)^2-38,[/tex] where the vertex is (4, -38).

Step-by-step explanation:  Given that the first steps in writing [tex]f(x)=3x^2-24x+10[/tex] in vertex form are shown.

[tex]f(x)=3(x^2-8x)+10~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

We are to write the given function in vertex form.

We know that

the vertex form of a function g(x) with vertex at the point (h, k) is given by

[tex]g(x)=a(x-h)^2+k.[/tex]

Therefore, from equation (i), we get

[tex]f(x)=3(x^2-8x)+10\\\\\Rightarrow f(x)=3(x^2-8x+16)-3\times 16+10\\\\\Rightarrow f(x)=3(x-4)^2-48+10\\\\\Rightarrow f(x)=3(x-4)^2-38.[/tex]

Thus, the required vertex form of the given function is

[tex]f(x)=3(x-4)^2-38,[/tex] where the vertex is (4, -38).

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