Question

What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form? x = –4 ± 2

Answer 1

Answer:

$x=-4\pm 2\sqrt{3}$

Step-by-step explanation:

We have been given formula of a function $f(x)=x^2+8x+4$. We are asked to find the zeros of our given function in simplest radical form.

We will use quadratic formula to solve our given problem.

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Upon substituting our given values in above formula we will get,

$x=\frac{-8\pm\sqrt{8^2-4*1*4}}{2*1}$

$x=\frac{-8\pm\sqrt{64-16}}{2}$

$x=\frac{-8\pm\sqrt{48}}{2}$

$x=\frac{-8}{2}\pm\frac{\sqrt{48}}{2}$

$x=-4\pm\frac{\sqrt{16*3}}{2}$

$x=-4\pm\frac{4\sqrt{3}}{2}$

$x=-4\pm 2\sqrt{3}$

Therefore, solutions for our given equation are $x=-4\pm 2\sqrt{3}$.

Answer 2

Answer:

a

Step-by-step explanation: