Question

What is the vertex of the graph of the quadratic function y = x^2 6x 10? (3, -1) (-3, -1) (-3, 1) (3, 1)

Answer 1

y= x^2 + 6x + 10
y=(x+6/2)^2-6/2^2+10
y=(x+3)^2-3^2+10
y=(x+3)^2-9+10
y=(x+3)^2+1