Respuesta :

Electron configuration of: 
Cr = 1s2 2s2 2p6 3s2 3p6 3d5 4s1 
Cr2+ = 1s2 2s2 2p6 3s2 3p6 3d4 

Cu = 1s2 2s2 2p6 3s2 3p6 3d10 4s1 
Cu2+ = 1s2 2s2 2p6 3s2 3p6 3d9 

Co = 1s2 2s2 2p6 3s2 3p6 3d7 4s2 
Co3+ = 1s2 2s2 2p6 3s2 3p6 3d6

s can max contain 2 electrons.
p can max contain 6 electrons.
d can max contain 10 electrons.
f can max contain 14 electrons.
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