Question

A basketball team has 12 players and the coach wants to pick which 5 players will start today's game. How many combinations are there for the coach to choose from?

A. 867
B. 1,248
C. 25
D. 792

Answer 1

95,040÷120 =792......... it's d

Answer 2

Answer:

D. 792.

Step-by-step explanation:

We have been given that a basketball team has 12 players and the coach wants to pick which 5 players will start today's game.

We will use combinations formula to solve our given problem. $C(n,r)=\frac{n!}{r!(n-r)!}$, where,

n = Number of total items,

r = Number of items being chosen at a time.

Upon substituting our given values in combinations formula we will get,

$C(12,5)=\frac{12!}{5!(12-5)!}$

$C(12,5)=\frac{12!}{5!*7!}$

$C(12,5)=\frac{12*11*10*9*8*7!}{5*4*3*2*1*7!}$

$C(12,5)=\frac{12*11*10*9*8}{5*4*3*2}$

$C(12,5)=11*9*8$

$C(12,5)=792$

Therefore, the coach can choose from 792 combinations and option D is the correct choice.