Question

find equation of line passimng through(1,6)¶llel to x-2y=6

Answer 1

since the given line is ll to the req. line, so
x-2y=62y = x - 6
y = (1/2)x - 3
slope = 1/2

equation of the req. line is
y - y1 = m(x - x1)
y - 6 = 1/2(x - 1)
2(y - 6) = 1(x - 1)
2y - 12 = x - 1
2y = x -1 + 12
2y = x + 11
y = (1/2)x + 11/2